Probability Distributions Question (1 Viewer)

hmim

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Hi,

Could someone, please kindly explain how they got the values for the probabilities in the table above.
 

carrotsss

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The chance of x=0 is:
  • When picking the first wallaby, there are 20 wallabies available and 11 of them aren’t from acacia flat (based on original numbers from question)
  • When picking the second wallaby, there are 19 wallabies available and 10 of them aren’t from acacia flat (because we just took one)
  • When picking the third wallaby, there are 18 wallabies available and 9 of them aren’t from acacia flat (because we’ve taken two)

So (11/20)*(10/19)*(9/18)=11/76

Repeat a similar process to find the rest of them
 

hmim

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The chance of x=0 is:
  • When picking the first wallaby, there are 20 wallabies available and 11 of them aren’t from acacia flat (based on original numbers from question)
  • When picking the second wallaby, there are 19 wallabies available and 10 of them aren’t from acacia flat (because we just took one)
  • When picking the third wallaby, there are 18 wallabies available and 9 of them aren’t from acacia flat (because we’ve taken two)

So (11/20)*(10/19)*(9/18)=11/76

Repeat a similar process to find the rest of them
thank you so much, that makes sense!
 

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