+1divided by m!n! since they are all identical
i got 13!/(10!*3!) pretty sure thats rightPart 2 was (4C1)^10 if I'm not wrong
yes one mark!divided by m!n! since they are all identical
well, obviously there is 0.3 ways of putting coins in boxes, geniuswas aii) 4^10/10!? - soudned like quite a dodgily worded question
holomorphic question?ai) (M+N)!/M!N!
aii) 13!/10!3! (as we put three dividers in amongst the 10 coins, thus creating 4 groups.)
If Carrot hadn't put his holomorphic question on the BOS trial I would have gotten that wrong.
bi) straight forward
bii) required manipulation, I was stretched for time so I didn't finish
biii) I believe it was pi/4
ci) p(k) = P(k different integers)*p(one of those k integers)
= (nPk/n^k)*(k/n)
= required expression
cii) simple inequality
ciii) didn't understand this
civ) didn't understand this.....
speak engrishholomorphic question?