Solutions (1 Viewer)

Thecorey0

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THese are my solutions - well answers. Remember these are by a student, and aren't necessarily right. Tell me if there is something wrong, as there most probaby is. Sorry for the horrible format. It won't let my upload either.

1b) x= 4/3
1c) x=4, -6
1d) m=1
1e) θ=π/3
1f) x= 7.3891

2ai) sinx +xcosx
2aii) 2e^x(e^x +1)
2bi) 5x + c
2bii) -3/(x-6) +c
2biii) 77/3
2c) 10

3a) 588
3bi) 4x-3y -5
3bii) 2
3biii) (x-1)^2 + (y-3)^2 = 4
3d) 64500m

4a) 12
4b) k=2, -6
4cii) 1:2

5ai) y=-x/root(3) +1
5aii) 2root(3)
5bi) 1/3
5bii) 1/3
5biii) (2/3)^5
5ci) θ=2π/3
5cii1) 2π/3
5cii2) 2(π/3 +1)

6a) 2πroot(3)
6bi) k=ln2/1600
6bii t=2536
6ci) b=12, a=-1/20
6cii) d=16.2

7aii) t=ln4
7aiii) x= 7/8 + ln4
7bi) T=12
7bii) h=0.3 t=2pm
7biii) 6-10am

8ai) 3>x>-1
8aii) the gradient approaches 0
8bi) $349688
8bii) $2270
8biii) 179 months
8biv) $129966

9a) 91/216
9bi) $12800
9bii) $15160
9biv) x= 5/4 c=$12200
9bv) p straight to s

10f) 17/12 -2ln2
 
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HTB

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off the top of my head (recalling the answers I wrote), they look about right

I also got something like that for the loan savings question and I was worried about that since the 2 people next to me got something else (one of them is ranked first in my school)
 

blackratpoo

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ok. i disagree 3 iii) equation of a circle. at a diff cente, you seem to think at origin??

5, ii) 1/3 also i put. worded wierdly though,
and is 9 v) really straight underwater. ??
 

xFusion

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ok. i disagree 3 iii) equation of a circle. at a diff cente, you seem to think at origin??

5, ii) 1/3 also i put. worded wierdly though,
and is 9 v) really straight underwater. ??
OMG looking at the answer I just realised I didnt read 9(v) properly =.=
Friggn found the cost instead.. erghh :mad1:
 

Bdogz

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For 4cii) i got the ratio as 1:1 since that is the only way you can prove that ABC can be divided into two isosceles triangles
 

carlytse621

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for 9bii, isn't we times $1000 with the distance PS?
since we times 1000 from R to S, so P to S shouldn't be 1000 as well?
I am scare :S
 

Currlz

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8ai) 3≥x≥-1

Would it not be 3>x>-1?

At -1 and 3 it will be 0?
 

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