trig question (1 Viewer)

martin310015

Member
Joined
Dec 12, 2003
Messages
80
Gender
Undisclosed
HSC
2004
having trouble with this questions, how would i start them ......

1.using double angle formula for tan@, find tan22/2degree in simplest surd form.

2.if tan@=k tan# , show that

(k-1)sin(@+#)=(k+1)sin(@-#)

thanx
 
Last edited:

Xayma

Lacking creativity
Joined
Sep 6, 2003
Messages
5,953
Gender
Undisclosed
HSC
N/A
Just to give you a start with number 1.

tan 2@=45 degrees
tan 2@= 2tan @/(1-tan<sup>2</sup> @)
but tan 2@=1
therefore
1=2tan @/(1-tan<sup>2</sup> @)

Work from there just some rearranging etc.
 

nike33

Member
Joined
Feb 18, 2004
Messages
219
for the second one, convet to sin / cos then use sum / product rules
 

martin310015

Member
Joined
Dec 12, 2003
Messages
80
Gender
Undisclosed
HSC
2004
Originally posted by Xayma
Just to give you a start with number 1.

tan 2@=45 degrees
tan 2@= 2tan @/(1-tan<sup>2</sup> @)
but tan 2@=1
therefore
1=2tan @/(1-tan<sup>2</sup> @)

Work from there just some rearranging etc.
i managed to do this one.

Originally posted by nike33
for the second one, convet to sin / cos then use sum / product rules
but for this one im still confused......
 

Xayma

Lacking creativity
Joined
Sep 6, 2003
Messages
5,953
Gender
Undisclosed
HSC
N/A
(k-1)sin(@+#)
=(k-1)(sin@cos#+cos@sin#)
=ksin@cos#-sin@cos#+kcos@sin#-cos@sin#
=ksin@cos#-tan@cos@cos#+ktan#cos@cos#-cos@sin#
=ksin@cos#-ktan#cos@cos#+tan@cos@cos#-cos@sin#
=ksin@cos#-ksin#cos@+sin@cos#-cos@sin#
=(k+1)sin@cos#-(k+1)sin#cos@
=(k+1)(sin@cos#-sin#cos@)
=(k+1)sin(@-#)
 

Heinz

The Musical Fruit
Joined
Oct 6, 2003
Messages
419
Location
Canberra
Gender
Male
HSC
2004
Let me give it a go

tan@=k tan#
sin@/cos@ = ksin#/cos#
sin@cos# = ksin#cos@

(k-1)sin(@+#)
= (k-1)(sin@cos# + cos@sin#)
= (k-1)(ksin#cos@ + cos@sin#)
= (k-1)(k+1)(sin#cos@)
= (k+1)(ksin#cos@-sin#cos@)
= (k+1)(sin@cos# -sin#cos@)
= (k+1)(sin(@-#)

hmm.... that isnt 3 lines.
 

nike33

Member
Joined
Feb 18, 2004
Messages
219
@ and # are evil anyhow (A=@, B=#)

2sinAcosB = 2kcosAsinB
sin(A+B) + sin(A-B) = ksin(A+B) - ksin(A-B)
(k-1)sin(A+B) = (k+1)sin(A-B)
 

nike33

Member
Joined
Feb 18, 2004
Messages
219
are product / sums on the 3 unit sylabus? or only 4unit? and in a 2u exam, we had a trig qn, the given answer was 11-12 lines (out of 5 marks) anyhow i did it in 3-4 lines using product/sum and got 0 lol.. i would do something but 2u doesnt count so meh
 

Heinz

The Musical Fruit
Joined
Oct 6, 2003
Messages
419
Location
Canberra
Gender
Male
HSC
2004
Originally posted by nike33
are product / sums on the 3 unit sylabus? or only 4unit? and in a 2u exam, we had a trig qn, the given answer was 11-12 lines (out of 5 marks) anyhow i did it in 3-4 lines using product/sum and got 0 lol.. i would do something but 2u doesnt count so meh
Nice solution. Sum and products are part of 3unit but no one bothers to learn them (unless you do 4unit)
 

Users Who Are Viewing This Thread (Users: 0, Guests: 1)

Top