Someone posted the following question:
5 dice are rolled. Find the:
a) Prob(getting 5 '6')
b) Prob(getting no '6')
c) Prob(at least 1 '6')
This is a very basic probability question and, being a 2U question, I'll post a 2U solution. My previous post disapppeared and I'm re-posting for the benefit of some 2U Maths students.
a) P(all a '5') = P(die-1 a '6') x P(die-2 a '6') x . . . . x P(die-5 a '6')
= (1/6)x(1/6)x . . . . x (1/6) = (1/6) 5
b) P(none a '6') = P(die-1 not a '6') x P(die-2 not a '6') x . . . . x P(die-5 not a '6')
= (5/6) x (5/6) x . . . . x (5/6) = (5/6) 5
c) P(at least one is a '6') = 1 - P(none a '6') = 1 - (5/6)5
5 dice are rolled. Find the:
a) Prob(getting 5 '6')
b) Prob(getting no '6')
c) Prob(at least 1 '6')
This is a very basic probability question and, being a 2U question, I'll post a 2U solution. My previous post disapppeared and I'm re-posting for the benefit of some 2U Maths students.
a) P(all a '5') = P(die-1 a '6') x P(die-2 a '6') x . . . . x P(die-5 a '6')
= (1/6)x(1/6)x . . . . x (1/6) = (1/6) 5
b) P(none a '6') = P(die-1 not a '6') x P(die-2 not a '6') x . . . . x P(die-5 not a '6')
= (5/6) x (5/6) x . . . . x (5/6) = (5/6) 5
c) P(at least one is a '6') = 1 - P(none a '6') = 1 - (5/6)5
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