2 Short answer questions (1 Viewer)

KFunk

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1. a)
at t=0 ---> M<sub>o</sub>e<sup>-kt</sup>=10 so M<sub>o</sub>=10
at t=140:
5=10e<sup>-140k</sup>
ln(1/2)=ln(e<sup>-140k</sup>)
-ln(1/2)/140= k so k = 4.95 x10<sup>-3</sup> to 2d.p.


b) After 70 days M = 10e<sup>-70k</sup> = 7.07 grams

c) 2= 10e<sup>-kt</sup>
1/5 = e<sup>-kt</sup>
ln(1/5) = -kt
t = -ln(1/5)/k = 325.07 days to 2d.p.
 

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