2006 catholic trial help (1 Viewer)

[n@ttyb]

i have looked at the worked answers and cannot work out for some questions how it was done.

Can someone help me with q'ns :

17
24 C
25 B: i + ii
26 C iv
27 B,

link to trial exam ------>​

http://www.boredofstudies.org/download.php?id=6706
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Edit: here is the link to the answers http://www.boredofstudies.org/download.php?id=6707
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[Nullz]

17)

= sine rule

x/9.8 = sin 37/15

= sin37/15 X 9.8

=0.393185815

=Shift Sin 0.393185815 = 23.15287593

17 = A

25b) i) - mean = 520, SD = 30.. 490 - 550 = 34% + 34% = 68%
ii)- 490 = 1 sd below mean, 460 = 2 SD below ...so 460
Sorry, not good at explaining this one..id need to draw it.

 

[berra]

i have looked at the worked answers and cannot work out for some questions how it was done.

Can someone help me with q'ns :

17​

24 C
25 B: i + ii
26 C iv
27 B,

http://www.boredofstudies.org/download.php?id=6707
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Q17. SINE RULE
what you do is:
1. sin x/9.8 = sin37 /15
2. [move 9.8 to the left, as u want to solve for x]...
sin x = sin37/15 (times) 9.8. this equals to : 0.393185815
3. now, to got x, you have to move the sin. press shift on ur calculator n then the sin button, and thats it. answer is 23 = a

Q.24 C
1. 5/2 = 2.5 (first captured and marked over the tagged ones in the second capture)
2. 2.5 X 10 = 25 (multiply the answer from part 1 with how many of them were captured in the second capture)
therefore, theres approx 25 of them.

Q 25 B (I & II)
mean= 520mm, st.dev= 30mm
i. it asks between 490 and 550.
so; 490 - 520/30 : gives a z-score of -1
550 - 520/30 : gives a z-score of 1
the percentage between these 2 z-scores are 68%... u jst have 2 memorise these (refer 2 ur textbook)

ii. between 2 standard deviations mean that the z-scores are -2 and 2.
you substitute; -2 = x - 520/30 ---- when u simplify, the x is 460 mm
this is the minimum length that the farmer will accept.

Q 26 C (IV)
1. angular distance is: 28+151 = 179 degrees
2. time difference = 179 x 4/60 : 11 hours, 56 min
3. therefore, 17+11:56 = 4:56 am

Q 27 B
cos O(theat.) = a/h --- cos 63 = x/24 --- simplify it, and x = 10.9 km


here u go!!! i dnt believe i was actually botherd 2 do all dat, but i guess i know how it feels 2 b helpless... since im in d same situation

 

[n@ttyb]

hey thanks guys

here u go!!! i dnt believe i was actually botherd 2 do all dat, but i guess i know how it feels 2 b helpless... since im in d same situation

yes im horrible at maths lol.... cant wait till its over !!

 

[Katherine2006]

Could someone tell me how you get 63 degrees for part Q27b (i) i get the rest just not that bit

 

[berra]

Could someone tell me how you get 63 degrees for part Q27b (i) i get the rest just not that bit

all u do is 90 - 27 = 63...
then,
cos 63 = x/24 to get d answer...

 

[hopeles5ly]

Can someone help me with Q28 C?
Thanks.

 

[hopeles5ly]

Q17. SINE RULE
what you do is:
1. sin x/9.8 = sin37 /15
2. [move 9.8 to the left, as u want to solve for x]...
sin x = sin37/15 (times) 9.8. this equals to : 0.393185815
3. now, to got x, you have to move the sin. press shift on ur calculator n then the sin button, and thats it. answer is 23 = a

Q.24 C
1. 5/2 = 2.5 (first captured and marked over the tagged ones in the second capture)
2. 2.5 X 10 = 25 (multiply the answer from part 1 with how many of them were captured in the second capture)
therefore, theres approx 25 of them.

Q 25 B (I & II)
mean= 520mm, st.dev= 30mm
i. it asks between 490 and 550.
so; 490 - 520/30 : gives a z-score of -1
550 - 520/30 : gives a z-score of 1
the percentage between these 2 z-scores are 68%... u jst have 2 memorise these (refer 2 ur textbook)

ii. between 2 standard deviations mean that the z-scores are -2 and 2.
you substitute; -2 = x - 520/30 ---- when u simplify, the x is 460 mm
this is the minimum length that the farmer will accept.

Q 26 C (IV)
1. angular distance is: 28+151 = 179 degrees
2. time difference = 179 x 4/60 : 11 hours, 56 min
3. therefore, 17+11:56 = 4:56 am

Q 27 B
cos O(theat.) = a/h --- cos 63 = x/24 --- simplify it, and x = 10.9 km


here u go!!! i dnt believe i was actually botherd 2 do all dat, but i guess i know how it feels 2 b helpless... since im in d same situation

You did Q26 C wrong.

It's 151-28=123
123/15=8.2hrs
8.2hrs - 5:00 =8:48

 

[housemouse]

lol
28
i) There are six sides to the rectangular prism so you have to find out the area of all the six sides then add them together

so it would be 2{x(9-x) + x(9-x) + x^2}

ii)it is only valid with values from 0 to 9 because you cant have negative values for the lengths such as for the side 9-x, you cant have any positive value exceeding nine and the other sides, you cant have a negative number as a value

iii) answer is x =6

iv) Do you guys do differentiation?

 

[PC]

28 (c) (iv) - no need for differentiation. Substitute x = 6 into the formula for surface area.

 

[berra]

You did Q26 C wrong.

It's 151-28=123
123/15=8.2hrs
8.2hrs - 5:00 =8:48

lol, im sorry.. i guess i wasnt paying attention, although therz a big zero on my paper.. n ryt next 2 it 2...

uhm, i gotsa question....but not from the SCCA paper... jst generally...
wif algebra... how do we simplify fractions, especially wen theres a minus, division or addition between em...

E.g.
x/3 - 7/5 = 9/10 - x/2

i realllyy get confusedd... can sum1 plz give tips.

p.s. to those who r gnna say 'go on a new thred this is bout CSSA', im only tryn 2 iincrease my chances of receiving a reply...
thnx

 

[housemouse]

28 (c) (iv) - no need for differentiation. Substitute x = 6 into the formula for surface area.

oh yeah