An easy question (1 Viewer)

[lazyandcool]

A force F acts between two masses separated by a distance d.if the masses are both doubled and separation is halved,the new force is ......? Can u explain in depth pls btw the answer is 16F but how.?

 

[jamesfirst]

I'm only presuming


F= Gm(1) m(2) / r^2


M1 and M2 is both multiplied by 2.

therefore M1 x M2 = 4M1 x M2


distance is halved


therefore (r/2)^2


F= G x 4 x M1 x M2 / (r/2)^2

F= G x 16 x M1 x M2 / r^2


Original force is G M1 M2 / r^2. So let the original force be 1.


Hence, Force is increased to 16 newtons. Since from the equation, the whole equation has been multiplied by 16. Which means that the original force has been bumped by to 16 times the original force.

 

[ohexploitable]