kkk579
hello
how do i do this q? would i expect thus in y11ext1 cos ngo never taught us smth like this
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- Thread starter kkk579
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kkk579
hello
moreos y12 adv
the long div part is less common and personally i just expand and add/subtract terms and then split fraction so it can cancel out
u could also work from the -x + 4 thing back to f(x) cause it seems easier (similar to how they can ask partial fraction in 2u
just go the reverse)
oblique asymptote is technically 3u though but idt you need to worry about it bcz it's not rly too hard for these types of qns
for ii, just state as x—> infty the fraction goes to 0
the long div part is less common and personally i just expand and add/subtract terms and then split fraction so it can cancel out
u could also work from the -x + 4 thing back to f(x) cause it seems easier (similar to how they can ask partial fraction in 2u
just go the reverse)oblique asymptote is technically 3u though but idt you need to worry about it bcz it's not rly too hard for these types of qns
for ii, just state as x—> infty the fraction goes to 0
kkk579
hello
how do u know to look at those specific x imtervals for iii tho? like i get that it comes from the quadratic but how do yk to do that?moreos y12 adv
the long div part is less common and personally i just expand and add/subtract terms and then split fraction so it can cancel out
u could also work from the -x + 4 thing back to f(x) cause it seems easier (similar to how they can ask partial fraction in 2u
oblique asymptote is technically 3u though but idt you need to worry about it bcz it's not rly too hard for these types of qns
for ii, just state as x—> infty the fraction goes to 0
sign table — check in between the numbers in the brackets and left /right kf fhem if ykwim
kkk579
hello
Yeah i get that but why do we look specifically at that? how about the denominator?
kkk579
hello
Cos what about the other part of the graph? Wpuldnt that also be entirely negative? The part on the graph on the other side of the vertical asynptote
ok so u can kinda ignore it tbh bcz it's a "bigger case" it's just like how in a quadratic which has 2 intercepts u know there's left centre and right
similar to you can use null factor theorum on the top brackets to get x intercepts
uhh wdym
kkk579
hello
Like beyond the point x=5 wouldnt there be another geaph similar to the one already drawn but just upside down
kkk579
hello
wdym by bigger case?
there is but they don't give enough space to consider it
like it has less intervals
kkk579
hello
i thought we would do f(x)>0 and solve it like an inequality so like times both sides by (5-x)^2 and then continue with that
for this case sign table is much quicker bcz u can just consider the intervals
what i meant by 'bigger case' is for x < 5 the denominator is always positive so you can kind of ignore it in that area and for x > 5 the denominator will be negative
then considering the top case, have more intervals to consider
kkk579
hello
wait, what i did is correct right? its just that in thr sol they didnt consider the graoh beyond x=5
kkk579
hello
thats why my sols r sloghtly diff from theirs
Where is the help needed?
I can solve it online for you. Contact on my email- pinky2286@gmail.com.
yeah it'd work just it's intended to do sign table because it's already factorised
kkk579
hello
Oh okay
kkk579
hello
to sketch the curve do i just use part i, graph the hyperbola and the linesr separately, then add the coordinates?