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HSC 2016 MX2 Integration Marathon (archive) (3 Viewers)

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Paradoxica

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Re: MX2 2016 Integration Marathon

The two sides are only equal down to an arbitrary constant. Hence, the conclusion that the two sides are identically equivalent is false. The error is revealed when you perform a definite integral, as opposed to an indefinite one.
 
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leehuan

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Re: MX2 2016 Integration Marathon



I don't know what I'm doing anymore


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Paradoxica

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Re: MX2 2016 Integration Marathon

I don't know what I'm doing anymore
You're getting there. Trust yourself. What you have can definitely be done using high school techniques. (That last one has been posted before by me)

Ironically, if you plug in my original question into Wolfram Mathematica, it can't find the closed form solution. But humans can do it.
 

leehuan

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Re: MX2 2016 Integration Marathon

Thinking about the symmetry about x=pi/4 but I've completely forgotten how to show it.

Besides that I might've figured it out.

EDIT: OH CRUD. f(x)=f(pi/2-x) isn't it.....
 

leehuan

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Re: MX2 2016 Integration Marathon




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