LOCUS question types - just a quick question (1 Viewer)

[psycho_orange01]

Hey, our class just started on LOCUS last lesson, and our teacher gave us the homework: write 3 of our own REAL DISTANCE questions, and 3 LOCUS questions and do them in our book.

Now, i wasnt completely sure what he meant. We didnt do much in class on the topic yet, it was only one lesson so far.

For the 3 locus questions i wrote some variations of "3 units from the point (2,-3)" and drew the circle and the formula for it (i.e. [ (x-2)^2 + (y+3)^2 = 3 ] ). I was pretty sure what he meant for the locus type questions...

For the real distance i didnt know, i guessed and wrote "3 units to the right of the y axis" and drew it... but...? I don't know what else to do - they were the only things we did in class...? help greatly appreciated!

 

[rama_v]

Um Im not quite sure, maybe he means a question like this:
"By using the perpendicular distance formula, find the locus of a point P(x,y) which is equidistant from the lines 3x + 4y =36 and 4x + 3y=24"??

 

[Trev]

For the 3 locus questions i wrote some variations of "3 units from the point (2,-3)" and drew the circle and the formula for it (i.e. [ (x-2)^2 + (y+3)^2 = 3 ] ). I was pretty sure what he meant for the locus type questions...

That would be incorrect anyway.
'Three units from the point (2,-3)", you should state the point as being the centre of circle, and radius of 3. But remember the equation of circle is as follows:
(x-h)²+(y-k)²=r²
Where centre circle (h,k) and radius is 'r'.
So the equation you wrote would be (x-2)²+(y+3)²=3²
(x-2)²+(y+3)²=9 (note: it is 9, not 3)

 

[KFunk]

Find the locus of the point P(x,y) that is equidistant from the line y=-1 and the point (0, 1)