Question (1 Viewer)

[Azreil]

For the question:
"For which values m does the equation sinx = mx have a solution in the domain 0 < x < pi ",
would we have to show working? I don't know the mark value of this part of the question. It's question 5ai) in http://www.boredofstudies.org/courses/maths/2u/1152574997_2006_Mathematics_HSC.pdf
if you wanted to have a look at the whole thing.

Thanks :]

 

[henry08]

Lol at the 5 hour maths paper created from past Q10 questions.

 

[Timothy.Siu]

For the question:
"For which values m does the equation sinx = mx have a solution in the domain 0 < x < pi ",
would we have to show working? I don't know the mark value of this part of the question. It's question 5ai) in http://www.boredofstudies.org/courses/maths/2u/1152574997_2006_Mathematics_HSC.pdf
if you wanted to have a look at the whole thing.

Thanks :]

well yes you would need working. how else can you do it? you have to show how you did it

 

[Charlesr]

This cant be right but
sinx = 0
therefore m could be... ANYTHING?
too simple i assume

 

[stormz89]

0 < m < 1

if you draw the two graphs you'll see it.

 

[Timothy.Siu]

This cant be right but
sinx = 0
therefore m could be... ANYTHING?
too simple i assume

0 isn't part of the domain

0 < m < 1

if you draw the two graphs you'll see it.

yeah thats correct because the gradient of the sin curve at 0 is 1, so, m has the be less than 1 and greater than 0 because thats the domain

 

[Charlesr]

ofcourse, here we see were I will lose all my marks
Reading the question

 

[lyounamu]

For the question:
"For which values m does the equation sinx = mx have a solution in the domain 0 < x < pi ",
would we have to show working? I don't know the mark value of this part of the question. It's question 5ai) in http://www.boredofstudies.org/courses/maths/2u/1152574997_2006_Mathematics_HSC.pdf
if you wanted to have a look at the whole thing.

Thanks :]

For this question, you really have to refer back to the question earlier on.

Since you found the tangent of the y=sinx to be y=x, if the gradient is larger than 1, no line will touch the graph y=sinx.

so 0 < m < 1

 

[Azreil]

So would you just have to say "as shown in above" or something? I understood the answer, I just didn't understand how you would verbalise the thought process that got you there.

 

[stormz89]

the good thing about maths is that you wouldn't actually need to verbalise this answer.

Because it says for which values. If it said show which values or something like that you would to have to explain.

 

[lyounamu]

So would you just have to say "as shown in above" or something? I understood the answer, I just didn't understand how you would verbalise the thought process that got you there.

That Or:

you can show what you have done in the earlier question over again as the question that you are asking doesn't include the word "hence".

I would personally draw a small sketch myself and show them that they tangent is at m=1 and tell them how m is between 0 and 1.

It shouldn't be too hard to get full mark in that as long as you don't contradict yourself...

 

[Azreil]

That Or:

you can show what you have done in the earlier question over again as the question that you are asking doesn't include the word "hence".

I would personally draw a small sketch myself and show them that they tangent is at m=1 and tell them how m is between 0 and 1.

It shouldn't be too hard to get full mark in that as long as you don't contradict yourself...

Thanks Namu and all ;]