Trig identity question (1 Viewer)

[Truly_bored]

Can anyone help me solve this trig question

sin @/1-cos@

@= theta

and the answer is 1+cos@/sin@

 

[perfectionist]

Do u mean that the answer is:

(1+cos @) / sin @

 

[Truly_bored]

yea

 

[perfectionist]

Sin @/ (1-cos @) = 1 + (cos @/ sin @ )

LHS = sin @/(1-cos@ ) X (1+ cos @)/(1+cos@)

= (sin @ + sin @ cos @) / (1- cos@)

= sin @/(1-cos@) + (sin @ cos @) / (1- cos @)

= sin @/sin@ + (sin @ cos @) / sin@

= 1/ sin @ + cos @ / sin @

= ( 1 + cos @) / sin @

= RHS

Hope this helps

 

[Truly_bored]

Hey Thanx Heaps!!!
I did try the questions a couple of time...got to about the third step like urs...and then bombed out...
I really appreciate ur help...
and once again thanx heaps...i knew it wasn't that hard of a question...

 

[perfectionist]

no worries

 

[Korn]

Can anyone help us out on how to work this out

Can anyone help me solve this trig question

(Sec^2@ -1)(1-sin^2@) = sin^2 @

@= theta

 

[Heinz]

Originally posted by Korn
Can anyone help me solve this trig question

(Sec^2@ -1)(1-sin^2@) = sin^2 @

@= theta

(Sec^2@ -1)(1-sin^2@) = (tan^2@)(cos^2@)
=(sin^2@/cos^2@)(cos^2@)
=sin^2@

 

[Korn]

Can anyone help me solve this trig question

PROVE
(Sec^2@ -1)(1-sin^2@) = sin^2 @

@= theta

 

[~*HSC 4 life*~]

LHS: (sec^2@-1)(1-sin^2@)
= tan^2@ x cos^2@
= sin^2@/cos^2@ x cos^@
= sin^2@
= RHS

 

[Korn]

Tnks man yor a life saver.