try this question (1 Viewer)

shaynO

New Member
Joined
Apr 19, 2003
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Location
sydney
try this question out...i thought of it a few years ago and it took me a few hours to work out the answer..

differentiate x^x (or in english x to the power of x)

have fun :)
 

spice girl

magic mirror
Joined
Aug 10, 2002
Messages
785
Use implicit differentiation (because you really really want to log the thing)

y = x^x
lny = xlnx

diff. r.t.x:
(1/y)dy/dx = (x*1/x + 1*lnx)
dy/dx = y(1+lnx) = x^x(1+lnx)
 

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