Rewards after HSC (2 Viewers)

[Nooblet94]

When he goes around a round-about, he thinks of the centripetal force and calculates it in his mind - so he is scared of the distraction.

When I was on my L's I almost went through a red light because I was busy doing a differentiation problem in my head. Let's just say my dearest mother was not pleased.

 

[MichelleV]

a subway foot long sandwich as a reward for a 99.15 atar I was content with that

I got a delicious pie as my reward.
It was delicious.

 

[Carrotsticks]

I got a delicious pie as my reward.
It was delicious.

What kind of pie?

 

[MichelleV]

What kind of pie?

Lamb and Rosemary <3

 

[Carrotsticks]

Oh my, how absolutely delicious.

Jelly.

 

[red-butterfly]

I didn't get anything .... no reward whatsoever :S

 

[Magical Kebab]

shit all for me i think. But isn't the reward just getting into the course you desire, or are you guys studying for ur parents lol?

 

[SpiralFlex]

My reward is a nice stroll along a beach.

 

[someth1ng]

When I was on my L's I almost went through a red light because I was busy doing a differentiation problem in my head. Let's just say my dearest mother was not pleased.

Are you joking...or are you serious? LOL

 

[lauren-c]

I got told a good result was the reward in itself... god darn it... should of pretended I wasn't at all intrinsically motivated ahha
I guess my 92.15 atar felt pretty good, but $$ would of been great.

A friend got offered any car of her choice if she got over 90... she didnt even try!
and another will get a new car if she gets in the 90s or if in the 80s her parents will split the cost of a second hand.

 

[inJust]

This is what my parents would say to me.

98+: A "Congratulations".
96-97: "Wanna clap?"
95: "I paid 13 years worth of school fees for this?"
<94: *Opens a big ol' can of ass whoppin'*

 

[SpiralFlex]

i have question on Polynomials, please help!!

Q: When a polynomial is divided by (2x+1)(x-3), the remainder is 3x - 1. What is the remainder when the polynomial is divided by (2x+1)?

Wrong place to post...

Division identity form,

 

[someth1ng]

Wrong place to post...

Division identity form,

So...put it in the P(x)=(2x...-1 form then use remainder theorem to find the remainder? So if it was divide by (x-3) instead, it would be subbing in 3 in the first equation and get 8?

 

[Bored_of_HSC]

i have question on Polynomials, please help!!

Q: When a polynomial is divided by (2x+1)(x-3), the remainder is 3x - 1. What is the remainder when the polynomial is divided by (2x+1)?

Wrong place to post...

Division identity form,

So...put it in the P(x)=(2x...-1 form then use remainder theorem to find the remainder? So if it was divide by (x-3) instead, it would be subbing in 3 in the first equation and get 8?

Shoo off back to the maths forum!!

 

[SpiralFlex]

So...put it in the P(x)=(2x...-1 form then use remainder theorem to find the remainder? So if it was divide by (x-3) instead, it would be subbing in 3 in the first equation and get 8?

Yes, but do you understand the theory behind it? Why I did it?

 

[zeebobDD]

Shoo off back to the maths forum!!

this site is infested with a whole mob of math nerds

 

[SpiralFlex]

Might have to beg for a puppy dog!

 

[gleeek]

95+ a trip to Paris and self fulfillment.

Oh and scaring the shiz out of my younger sister since she will have the pressure to beat me

 

[wildchild666]

Might have to beg for a puppy dog!

I <3 my dog.

 

[someth1ng]

Yes, but do you understand the theory behind it? Why I did it?

Yeah, sometimes it's shown as P(x)=(2x+1)(x-3)A(x)+3x-1 --> using remainder theorem, you sub in and you find the remainder.