Calculus & Analysis Marathon & Questions (7 Viewers)

seanieg89

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Re: First Year Uni Calculus Marathon

The coefficients of xk will be ak/k!...

If you wanted my naive first contruction...
The coefficients of x^k in what?

It is true that:

has for but the formal expression

need not converge anywhere apart from

This is a decent place to start from though.
 

Paradoxica

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Re: First Year Uni Calculus Marathon

The coefficients of x^k in what?

It is true that:

has for but the formal expression

need not converge anywhere apart from

This is a decent place to start from though.
The rest is based upon the radius of convergence, or am I jumping too far in?
 

seanieg89

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Re: First Year Uni Calculus Marathon

The rest is based upon the radius of convergence, or am I jumping too far in?
That is what makes this problem interesting though, the (a_n) are unspecified.

If the (a_n) were (say) bounded, then the Taylor series would have a positive radius of convergence, and from some basic analysis, the limiting sum would be a smooth function inside its disk of convergence with the desired properties. It is not so hard to extend such a function to be smooth on the whole real line.

However if the a_n grow rapidly in size, then this series need not converge ANYWHERE other than at x=0 (ie radius of convergence is 0). In this case it is not clear whether or not we can construct a smooth f with the desired properties, which is what makes the question of interest.
 

Drsoccerball

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Re: First Year Uni Calculus Marathon

Basically use induction and the axioms of commutativity and associativity of the addition operation.
induction how ?
Where do you put which brackets originally?
 

seanieg89

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Re: First Year Uni Calculus Marathon

Here's a cool one to think about:

Bump.

Fun fact, am currently proving a predictable generalisation of this theorem's big brother for use in attacking a thesis problem. Will give a brief outline to show how easier problems can lead to pretty strong and useful results.

So classically, we define the notion of differentiability on open sets, that is sets where we can find small balls about any given point that are contained in our set.

Given a set K that is instead compact (bounded and with open complement if we are talking about Euclidean space R^d), and continuous functions f_alpha on K, when can we find a smooth function g on R^d such that the (alpha)-th derivative of g is f_alpha? (Here alpha ranges over multi-indices if d > 1. In the d=1 case alpha is just a non-negative integer.) The theorem that resolves this question is called the Whitney extension theorem, and the question I posed earlier is the Borel theorem, which is the special case where K is just a single point. The Borel theorem can be used as a stepping stone to a proof of the Whitney theorem.

We can ask the same question with "smooth" replaced by a stricter notion of regularity. In my case this is something called the Gevrey class. (Gevrey functions can be thought of as a sliding scale between functions that are merely smooth and functions that are analytic, which is a strong property indeed). In this case, we also have a version of the Whitney extension theorem, although of course the functions f_alpha have to obey stronger properties for an extension to exist.

My version involves functions f(x,y) where x and y live in compact sets in euclidean spaces, but f has different orders of Gevrey regularity in x and y (we call these kinds of function spaces with differing regularity anisotropic). The question is then whether or not there exists an extension of the same anisotropic Gevrey regularity. It is not super hard to answer given the results already established in the non-anisotropic case, but some of the estimates are a little tedious.
 

davidgoes4wce

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Re: First Year Uni Calculus Marathon

I assume in this question our answer must be close to





^^That question was using right end points. I am just lost when involving the midpoint as I can't seem to cancel any terms. Going back through the question I don't think it asked us to specify exactly which Riemann we should have used, whether it be Left, Right or Midpoint.

Here was my attempt at doing this question:




I think this question maybe we have to make an assumption on 1) number of intervals and 2) which points we select (left, right or midpoint).
 

seanieg89

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Re: First Year Uni Calculus Marathon

I assume in this question our answer must be close to





^^That question was using right end points. I am just lost when involving the midpoint as I can't seem to cancel any terms. Going back through the question I don't think it asked us to specify exactly which Riemann we should have used, whether it be Left, Right or Midpoint.

Here was my attempt at doing this question:




I think this question maybe we have to make an assumption on 1) number of intervals and 2) which points we select (left, right or midpoint).
The second equation in your last page should have a +, not a -. You have also lost a pi somewhere as it will appear in the argument of all four trig functions.

These mistakes aside, you can make this calculation work. Notice that when you are summing (pi/4n).sin(pi*k/4n).sin(pi/8n) from k=1 to n, you are summing n terms, each bounded by a constant multiple of 1/n^2. Such a sum must then tend to zero, so you are left with the other term which is the sum of (pi/4n).cos(pi*k/4n).cos(pi/8n) from k=1 to n. The identity given in your hint tells you how to sum this, and then you just need to compute the limit as n->inf which follows from basic limit laws and trig limits.

The left/right endpoint Riemann sum would have been simpler to compute just because you wouldn't have to do the first step of expanding cos(pi*k/4n-pi/8n) and dealing with the negligible error term, but it's otherwise the same kind of calculation, and of course the same limit.
 
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davidgoes4wce

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Re: First Year Uni Calculus Marathon

I tried to write a neater version of my working out:



I still dont understand why you say the sin component is equal to 0, I did manage to simplify it down to: sin (pi/4n). sin(pi.k/4n).sin(pi/8n) . I still dont quite understand the multiple 1/n^2 bounded by that.
 

seanieg89

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Re: First Year Uni Calculus Marathon

Didn't know you could go from

sin(x) < x for positive x is a pretty well-known inequality. Depending on your way of defining the sine function, this inequality might either be obvious, or just a consequence of integrating the inequality 1-cos(t) >= 0.
 

seanieg89

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Re: First Year Uni Calculus Marathon

So as I said, use the "hint" provided in the question to evaluate the sum and then calculating the limit will be fairly straightforward.
 

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