synthesisFR
Well-Known Member
i post questions here for u to answer
but what i did was also correct?look at the original eqns, y=1/sqrt(1-t^2) cant be negative
ok no this is impossible if u cant do it then imma move onno clue i got dx/dt=0.15x
u bastard this is my threadGUYS GUYS GUYS WHAT IS THE QUICK WAY TO SOLVE QUESTIONS?????
4u grammar 2021
View attachment 39578
answer is B
penrith 2022well its common sense like its removing 15% of x per one t i dont rlly see how itd be anything else
what paper is this from
idrk, now it's become a general mx1 mx2 help thread <3u bastard this is my thread
bro tf I was born therepenrith 2022
wow. that's awesome.bro tf I was born there
^ ? $ ! ( ) ! zyx thanksGUYS GUYS GUYS WHAT IS THE QUICK WAY TO SOLVE QUESTIONS?????
4u grammar 2021
View attachment 39578
answer is B
go away math advanced studentwow. that's awesome.
for statement I and II, the limits have an equal length in the positive and negative quadrants, so if u draw it out, for them to be equal to 0 the integrals must be odd functions. I clearly isn't odd by virtue of having an x^2, in II the sec^3 and tan^2 are both even functions and only the remaining tan is an odd function, so an even*odd function = odd function therefore II is true. then its just logic for cos^3, cos has an x intercept at pi/2 so it makes sense that the positive and negative halves would cancel out. hence BGUYS GUYS GUYS WHAT IS THE QUICK WAY TO SOLVE QUESTIONS?????
4u grammar 2021
View attachment 39578
answer is B
i do 3u but okay... u piss offgo away math advanced student
latin ext student*go away math advanced student
@carrotsss ^^ you have a shortcut for this?GUYS GUYS GUYS WHAT IS THE QUICK WAY TO SOLVE QUESTIONS?????
4u grammar 2021
View attachment 39578
answer is B
for statement I and II, the limits have an equal length in the positive and negative quadrants, so if u draw it out, for them to be equal to 0 the integrals must be odd functions. I clearly isn't odd by virtue of having an x^2, in II the sec^3 and tan^2 are both even functions and only the remaining tan is an odd function, so an even*odd function = odd function therefore II is true. then its just logic for cos^3, cos has an x intercept at pi/2 so it makes sense that the positive and negative halves would cancel out. hence B