cmanassa

QUESTION 27c 3 raffles - 100 tickets each MARY: 2/100 = 1/50 = 0.02 (1 mark) JANE: Propability of winning both ticks is 1/100 x 1/100 = 1/10,000 (1 mark) Probabilty of winning first draw but not the second = 1/100 x 99/100 = 99/10,000 Propability of winning second but not first = 99/100 x 1/100 = 99/10,000 CONCLUSION... Propability of winning AT LEAST 1 (is the sum of the above 3 calculations) 1/10 000 plus 99/10 000 plus 99/10 000 = 199/10 000 = 0.0199 (1 mark) Hence, mary has a slightly beter chance... (1 mark)

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