I was really unsure about it because the answer my teacher posted was the following.
n = cV
n (Ba(OH)2) = 0.060 x 0.5 = 0.03 mol
n(OH)2 = 0.03/2 x 0.015
m = 0.015 x (137 + 2 x (16 + 1.0)) = 0.03 x 171 = 2.6 g
I have no idea what she is doing and the last line does not even work...
If its not a violation of copyright or anything.. it is possible for anyone to send a digital copy of a year 11 Pearson's chem textbook to me?
If you happen to have one and are willing to send, can you please dm me and i will send you my email.
So i am a year 10 but a lot of people here seems to doing this Atar estimation thing. I was wondering if you could give me an idea of what my atar would be if year 11 and 12 were to go as im doing at school right now. I know these marks wont accurately reflect my performance but here it...