Recent content by kingkong123

No, I agree, I never said he was WRONG, I said it is not completely correct. I agree with his comment that an experiment that achieves consistent results which are not completely valid (due to wrong experimental method, etc.) is not completely reliable, but for the scope of the HSC I think...

I don't think this is completely correct. Reliability is indeed a measure of how consistent the results are - even if they are incorrect. Take an archery shooter as an example. Consider someone who never hits the bulls eye, but they consistently shot the number 9, they are a reliable shooter...

The trace elements are known. AAS is just a method to detect their concentrations. Prior to AAS' development, experimental methods could not detect the presence of trace elements because they were in such low concentration. Once AAS was developed, it was found that trace elements existed in...

Q13 Cii (0 Displacement question) Yo, Did you guys sub in x=0 or x=5 to calculate the time when the particle first has 0 displacement? Having been asked to convert the particle's acceleration in a form that reveals its centre of motion in part (i), i used the definition that DISPLACEMENT is...

+1 i agree

I also thought this in the exam, and I worked out the length of AB thinking that the angled cross section was a part of an ellipse. It turned out to be really messy so i then assumed that the angled cross section was an arc of the circle and I ended up getting a much neater answer (which was the...

I did my working out and said \therefore $ The locus of the midpoint of $B_1B_2$ is $\frac{(u_1+u_2)+i(u_2-u_1)}{2} But i didn't specifically say that it is a fixed point. Would i lose any marks?

Oi deswa clear inbox

Re: General Thoughts: Mathematics Ext 2 yep i got that as well

sick resource lad

Re: Official BOS Mathematics Trial Examinations: Spring Edition. nice question. dat der squeeze theorem

quality question

im keen to see it as well :)

i got <a href="http://www.codecogs.com/eqnedit.php?latex=\frac{3\pi\sqrt2}{140}$ units^{3}" target="_blank"><img src="http://latex.codecogs.com/gif.latex?\frac{3\pi\sqrt2}{140}$ units^{3}" title="\frac{3\pi\sqrt2}{140}$ units^{3}" /></a>

unaware of copypasta