Is there anyone here who has selected Chemistry 1 at Friday 9am who still has more than that option? My timetable is looking quite horrible at the moment and I would definitely appreciate it if someone selects another time that they are comfortable with. I just at least need to fix my chemistry...
Okay
1) Find the first derivative of y = 3x² - 2x - 4, which is y' = 6x - 2
2) Re-arrange the line 2x - 3y + 7 = 0 into y = mx + b so I can find the gradient 'm' which is 2/3
3) Since for perpendicular m1.m2 = - 1, thus (6x - 2)x(2/3) = - 1
4) Multiplying them, (12x - 4)/(3) = - 1
5) 12x - 4 =...
Find the x-coordinate of the point on the curve y = 3x² - 2x - 4 where the tangent is perpendicular to the line 2x - 3y + 7 = 0.
Can someone tell me where I did a mistake or if I did the whole thing completely wrong.
(dy/dx) = 6x - 2
3y = 2x + 7
y = (2/3)x + (7/3)
(6x - 2)(-3/2) = - 1
[(-...