Recent content by Sstormwolf22

I think you can still use remainder theorem? Factorise the divisor into x(x+1) Using remainder theorem in the original polynomial, we know that: P(0)=3 and P(-1)=5 Using the polynomial in division form: P(x)=x(x+1)Q(x) + (ax+3) We know that P(-1)=5, so sub it into the divison form to get...

Chem Only = 27 - 8 = 19 Phys Only = 21 - 8 = 13 Neither Chem or Phys = 50 - 19 - 13 - 8 = 10 Therefore 10/50 = 1/5 Idk i'm not the best at probability lol