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No restrictions = 6! But two cant sit together so its 6! - the times they do sit together = 6! - (5!x2!) = 6! - (240) = 480 I think, this is my worst topic :(

Very true Most people (including me) would never be able to get those in exam conditions.

Heres the solution I typed it up a couple of weeks ago, found it lying around :)

lol, thanks for the compliment, but Im not really that good... Its just practise with these questions though i guess, like for example as soon as u see C0 included that automatically means that either they've integrated the identity, or that they've multiplied through by x. This is true...

Stuff like 2n = C0 + C1 + ... + Cn

Solution to Question 29 Next Question: Using the substitution t = tan@ , or otherwise, show: (tan2@ - tan@) / (tan2@ + cot@) = tan2@

Dont worry There will always be one or two questions that hardly anyone in the state will be able to do (namely some hard probability question or the very last question) Whats most important is that you dont waste time focusing on those questions - make sure you get 100% in the questions you...

pfft Binomial is easy once you learn how to do 3 or 4 of those hard ones. The projectile ones are nearly impossible, especially the very last question in 2000 and 1995.

I should have done Maths Extension 2 Our teacher scared us out of it :(

The markers will read everything thats written, whether its crossed out, written on ruled pages, or unrulsed pages, whether its under the heading"DO NOT MARK" - in short, they read EVERYTHING adn will give you marks accordingly In addition dont fret if you wrote two questions in teh same...

Actually while the previous years questions might look challenging the thing to remember is that they are all just differneitation and minimisation/maximisation. Once you get past the algebra its actually very simple. But in todays question it requried a fair bit of logical thinking

Yeah Question 10 was no way more difficult than in 2000 The 2000 was so obscure and ridiculous, and it was worth four marks! But what did make question 10 in this exam so hard was the time factor, little else.

Yeah I checked again, the answer is not 30 minutes, its 17 minutes or so, too bad I couldnt work it out in the exam :( Oh well, theres always 3 unit

From what ive seen Phantasmagoria will probably get first in the state, he seems really smart and got the last question :D What would 110/120 usually align to? 96?

You had to split it up by rotating the y = x^2 around the y axis from 0 to 4 or whatever and then teh other curve around teh y axis from 4 to 12.

I put down 2017 because 12.25 was 12 years and a bit I think the year is still 2017 even though its the 2018th year, liek for example this is the 2006th year even though we say its 2005. I think a similar question was in last years paper and u had to similalrly round down.

The main difficulty with question 10 was interpreting the question and, more importantly, the time factor - it was a long exam so most ppl (me included) had to rush the last question so we could check over the other questions, hence getting the question wrong :(

yep i got m/2 and m^2/4 for that question

For 10 a i x^2 - mx - b = 0 the solutions to this equation are x = alpha and x = beta alpha + beta = -b/1 = (m/1) = m (sum of roots) therefore: alpha + beta = m SImilarly alpha beta = c/a = -b

What did everyone get for the very last question? Was it 30 minutes (I ended up with a quadratic in t and solved it to get 30 - but im not sure if its right?)