The area in the first quadrant bound by y = (9 - x^2), y=0 and y=9 is rotated about the y axis. Calculate the volume of the solid generated.
I keep getting:
Pi * Integral between 9/0 (9-x^2)^2
= " 81 - 18x^2 + x^4 - 0
= " 81x - [18x^3]/3 + [x^5]/5 - 0
= Pi * 81(9) -...