Search results

Re: HSC 2013 2U Marathon x=0.207614169

Re: HSC 2013 2U Marathon <a href="http://www.codecogs.com/eqnedit.php?latex=\sin&space;x&space;=&space;\frac{1}{2}" target="_blank"><img src="http://latex.codecogs.com/gif.latex?\sin&space;x&space;=&space;\frac{1}{2}" title="\sin x = \frac{1}{2}" /></a> <a...

Re: HSC 2013 2U Marathon is their a limit such as 0 < x < 2pi?

Re: HSC 2013 2U Marathon 1/6 ?

Re: HSC 2013 2U Marathon My bad, but thanks for the help people!

Re: HSC 2013 2U Marathon <a href="http://www.codecogs.com/eqnedit.php?latex=y&space;=&space;5^{x}" target="_blank"><img src="http://latex.codecogs.com/gif.latex?y&space;=&space;5^{x}" title="y = 5^{x}" /></a> <a href="http://www.codecogs.com/eqnedit.php?latex=\log_{5}y&space;=&space;x"...

Re: HSC 2013 2U Marathon Oh i get it! so would it be <a href="http://www.codecogs.com/eqnedit.php?latex=\frac{\pi&space;(-1)^{2}}{4}&space;&plus;&space;\frac{1}{2}.1.1&space;&plus;&space;3.(-1)" target="_blank"><img...

Re: HSC 2013 2U Marathon still not it

Re: HSC 2013 2U Marathon im completely stuck -.-

Re: HSC 2013 2U Marathon is the function pi +14/4 though, the thing we just proved?

Re: HSC 2013 2U Marathon nope thats not it

Re: HSC 2013 2U Marathon It is.. hint: you have to use log laws to change to a base of e

Re: HSC 2013 2U Marathon woops!

Re: HSC 2013 2U Marathon <a href="http://www.codecogs.com/eqnedit.php?latex=Area&space;=&space;\frac{\pi&space;r^{2}}{4}&space;&plus;&space;\frac{1}{2}.b.h&space;&plus;&space;l.h" target="_blank"><img...

Re: HSC 2013 2U Marathon <a href="http://www.codecogs.com/eqnedit.php?latex=\textup{Find&space;the&space;derivative&space;of&space;}&space;5^{x}" target="_blank"><img src="http://latex.codecogs.com/gif.latex?\textup{Find&space;the&space;derivative&space;of&space;}&space;5^{x}"...

Re: HSC 2013 2U Marathon <a href="http://www.codecogs.com/eqnedit.php?latex=\frac{\partial&space;}{\partial&space;x}[xtan3x]&space;=&space;x.3sec^{2}3x&plus;1.tan3x=&space;3xsec^{2}3x&plus;tan3x" target="_blank"><img...

Re: HSC 2013 2U Marathon I know, i corrected it using the 2 unit method, and what do you mean?

Re: HSC 2013 2U Marathon <a...

Okay, thankyou heaps!

For a question like this, how much working out should i show, if i can do it in this many steps? its 3 marks by the way <a...