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Probability Ext 1 hard question
Just choose any 5 digits from 1 to 9 (omit 0 since your number has to have digits in increasing order, and we don't want 0 at the front) So 9C5, and there's only 1 arrangement of them which is in ascending order. Total number of 5 digit numbers = 9*10^4 (since 0 can't be at the front) Thus P =...- Ood
- Post #2
- Forum: Mathematics Extension 1
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