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Time to rock and roll. Our gratitudes, carroty! =D

My solution was \sqrt{\frac{189}{20}}, yeah, using Carrot's method.

Great job! =D In 14 c ii - shouldn't the first term be \tan \theta rather than simply \theta?

Re: HSC 2013 4U Marathon Dear god what did you draw. Also I have no question to give and apologise for that. ;-;

Re: HSC 2013 4U Marathon I worked out a rudimentary (and probably flawed) way of solving it, but it requires solving \theta - \tan \theta =2\pi, which I cannot do. So :spin:. Here is basically the way I was doing it: http://i.imgur.com/voDXmVw.png The dark blue is a semicircle. The green is...

That 4U was intense. Exhilirating & backbreaking paper. I enjoyed it in a masochistic kind of way.

Confirm for 4U.

In for 4U.