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Ok this is how it goes: A shell is fired with Velocity (V) with and angle of elevation (a[alpha]) from a gun at point (o). From point (o) a hill extends at angle (theta) Given: x = V.t.cos(a) y = -1/2 .g.t^2 + v.t.sin(a) and the time when the shell collides with the ground is T = R.cos(theta) /...