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  1. G

    Integrate e^-(x^2)

    I think there is an easier way to do this. We know that the probability density function of a standard normal distribution is: f(x) = \frac{e^{-{x^2}/{2}}}{\sqrt{2\pi}} We know that \int^{\infty}_{-\infty}{f(x)dx}=1 Therefore...
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