How many conflicting perspectives/related materials is everybody using.
Not sure if i should do 2 and 2 or 3 and 3. if i do 3 and 3 i can do one place, one even and one situation?
Hey Boxy, how crap were those section 1 texts. None of them mad any sense whatsover. I swear i got like 6/15 for that section ...grrrr.
The other two were pretty sweet, i aced creative but essay was a bit all over the place without my second piece of RM.
nope, can't do it. i know it uses a rule to switch them all around and get rid of the log but i can't remember it.
Does it go something like: (3x - 4) = 2^5 ?
Booyah! :) okay next question:
A ball is dropped from a height of 2 metres onto a hard floor and bounces. After each bounce, the maximum height reached by the ball is 75% of the previous maximum height. Thus, after it first hits the floor, it reaches a height of 1.5 metres before falling...
Geeze you get around boxhunter91 hahah every thread I read you've posted on hahah. Okay to your question:
a) P(RRR) = P(R) x P(R) X P(R)
= 1/3 X 99/299 X 98/298
= 1617/44551 = about 3.6%
b) P(Not red) = 1 - P(RRR)
= 42934/44551 = about 96.4%
c) P(RBG) = P(RBG) + P(BGR) + (RGB) + P(BRG) +...
Bali? that will be awesome :) and yeah normally summer holidays, its getting crazy popular now though. The bitch at the caravan park won't let us stay there tho, she was like 'I bet you aren't all over 18' so we're gunna have to rent a house for the week.
Okay time for a new question:
If a sector har an arc length of 3pi and a radius of 4units,
a) what is the angle (exact)
and b) calculate the area of the sector.
Okay for the first question, the most likely combination:
P(GGG) = (3/4)^3 = 27/64
P(2xG, 1xR) = P(GGR) + P(GRG) + P(RGG)
= 3(3/4.3/4.1.4) = 9/64
So the most likely is getting 3 green lights
And for the Second Question:
i) P(NN) = P(N) x P(N) = (0.15)^2 = 0.0225
ii) P(Has phone and used in...
b^2-4ac = 0
k^2-4.2.(3k-10)
k^2-24k+80=0
(k-20)(k-4) = 0
k=20 and k=4
Okay how about:
I drive through 3 sets of traffic lights, the probability
that each will be red is 0.25 and green is 0.75
Find the probability that all 3 lights are red.
Booyah series is my fave.
a) okay well: t3 = a + 2d = 32...(1) and t6 = a + 5d = 17...(2)
(2) - (1) = 3d = -15 so d = -5
sub d = -5 into (1) to get a
a - 10 = 32, so a = 42
b) sum to 10 terms = 10/2 (42 + (9 x -5))
S10 = 5(-3) = -15 (i think)
Okay try:
factorise x^3 - 27
hahah im such an idiot i did that question yesterday.
okay base angle = 62.4349... degrees
to change to rads x pi/180
therefore x = 1.107148718 rads
tan is positive in 1st + 3rd quadrants
so x = 1.11 (2dp) and x = pi + 1.107... = 4.25 (2dp)
Okay next question
Solve the pair of...