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English (Advanced) Paper 1 - 14th October English (Advanced) Paper 2 - 15th October Mathematics Extension 2 - 22nd October Mathematics Extension 1 - 24th October Chemistry - 30th October Physics - 1st November

Hey dude! do you remember me? how did you go in 2u HSC?

Since the x values of the intercepts is symmetrical AND y=x^2 is an even function hence the y-value is the same therefore discrim=0 y^2 + y(1-2c) + (c^2 - R^2) = 0 (1-2c)^2 - 4(1)(c^2 - r^2) = 0 1 - 4c + 4c^2 - 4c^2 + 4r^2 = 0 1 - 4c + 4r^2 1+4r^2 = 4c

Here is my solution to cii (differs from EVERYONE i've seen so far) from the quadratic: y^2 + y(1-2c) + (c^2 - R^2) = 0 The intersection between the circle and parabola is always positive (y-value) hence (root1) + (root2) > 0 root1 + root2 = -b/a = (2c-1) therefore 2c-1>0 2c > 1 c > 1/2

English Advanced Mathematics Extension 1 Mathematics Extension 2 Chemistry Physics Biology (Intending to drop sometime throughout the year) Aim: ALL ROUNDERS

The answer is 21, I misread the question and found number of terms instead of sum and got 241.

99/100 got the easy garden rows multiple choice question wrong ><

no, i remember it just asked, not specifying anything, I just labelled it 2dp. but YOU are more correct than me for leaving it in exact form.

increasing, at a rate of 0.91 (2.dp)

our Catholic paper did not have a discriminant at ALL, and it was unedited

are you 100% sure the answer is v=0?, or did I have to estimate it?

What were the solutions for the Q16 a velocity/time graph?

Re: A particle P is moving along the x-axis. Its position at time t seconds is given ok, ill explain this question to you 5)Calculate the total distance travelled by the particle in the first 'pi' seconds. Now, it means distance travelled, automatically know you have to refer to the integral...

Mathematics (Advanced) - 22/10/12 9:25AM

hahaha, Maths In Focus questions Q9. you construct a straight line from centre to chord, making a right angle triangle. now, you need radius, which is a length in this right angle triangle. (pi/6)/2 = pi/12 (new line constructed halves) sin(pi/12) = 12.5/x x = 12.5/sin(pi/12) now L = theta*r...

isnt it -3pi/4?