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A
pH calculation question
I worked out which was in excess ... i.e HCL by 0.0001 moles. As it is a strong monoprotic acid then there will be 0.0001 moles of hydronium ions 50.0 ml of solution. That will give concentration of hydronium ions with c=n/v and then ph=-log[H] . Hope this makes sense , its a bit of work for... -