still need help. did you manage to work it out?
i got this far:
2HCl + Ba(OH)2 --> BaCl2 + 2H2O
I know no. of moles for HCl is 0.01875mol
no. of moles for Ba(OH)2 is 0.005mol
i know the HCl is in excess but where do i go from here?
Hey, can anyone help me with this question?
Calculate the pH of the resulting solution when 25.0mL of 0.750 mol/Lhydrochloric acid solution is added to 10.0 mL of 0.500 mol/L of barium hydroxide solution???
Thanks!!!! :)