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Common denominate the fractions, then notice the numerator simplifies to a sine expansion identity in the form of sin(A - B), which can then be simplified and expanded again to get the answer.

I had this problem 2 years when I did the IPT paper for accelerated. All I can say is, this amount of freaking out isn't going to help, it just makes things worse. Much of the IPT course consists of pure memorisation; my entire study program for IPT to prep for the exam was to shut my door, flip...

An easier way would be to do this geometrically. Because the result is purely imaginary, we can simply say that arg[(z+2)/(z-4i)] = +/- (pi/2). Subsequently, arg (z+2) - arg (z-4i) = +/- (pi/2). The shape itself becomes a circle, with z+2 and z-4i as two points on the circle that, when you...

If we have a look at the equation, we see that the eccentricity of this hyperbola is the square root of 1+9^2/3^2. i.e. eccentricity = 2. If we then look at the focus of this hyperbola, we see that it is 2(sqrt3), which is also the x-coordinate of P. Therefore we know that since P is the...

Well, basically, although 4 unit is extension 2 maths, it's more like one subject heaped on top of 3 unit, which is one subject heaped onto 2 unit. The difficulty of 4 unit maths comes primarily from the complexity of algebra in most places, because I've been recently writing equations that...