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  1. T

    E4 Cutoff predictions?

    Just my opinion, from what I saw, the paper seemed hard at first glance but isn't really. Everything was standard (with usual plus minus few tricks) up until Q15. Q15(ii) just needed one small trick. Q16 needed basic understanding of complex numbers and probability question was very doable, in...
  2. T

    Carrotsticks' Solutions 2015 Extension 1 HSC

    hmm, but i just used y/x not ydot/xdot and got the answer pi/6 lol, so I prob lose 1 mark? or would they be nice and only consider the magnitude of the answer in ii as direction is in iii
  3. T

    Carrotsticks' Solutions 2015 Extension 1 HSC

    is it ok to just get pi/6 for the the projectile? I proved that time is after max height in (iii) hence it is down but I used y/x in part ii and still got the same magnitude so would I still get the marks?
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    Terry Lee's Solutions 2015 Extension 2 HSC

    Sorry I just realised (nq)(nq-1).....(nq-q+1) has q terms Ok i just realised how to solve it algebraically n^q(q!)/(nq)(nq-1)(nq-2).....(nq-q+1) (nq)(nq-1)(nq-2).....(nq-q+1)=n^q(q)(q-1/n)(q-2/n)....... tf (q!)/(q)(q-1/n)(q-2/n)....... n tends to infinity =q!/q^q
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    Terry Lee's Solutions 2015 Extension 2 HSC

    But logically it does make sense, as n tends to infinity, the number of possible squares for the black counters to be in the same column increases. I'm not too sure either but I think its also possible to show that algebraically. Pn=(n^q)(nq-q)!(q!)/(nq)! = (n^q)(q!)/(nq)(nq-1).....(nq-q+1)...
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