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geez man u serzly fink imma gonna go write full english sentences in a maths forum?? not to mention, i dont have to do f@#$ing english anymore either!!

wut da?? it seys acceleration is a constant....in otha words dv/dt=-9.8 not da/dt....i dun fink there is such a thing as da/dt in da course...

another acceptable answer to qu is x=6sin(2t+pi/6) i like this form rather than cos fro some reason....

final answer is: 1/2[(u^5)/5 -3/2(u^4)] +c with u=6+x^2 ive checked it so im pretty sure but u can check it agen if u want...btw i did this thru substitution of u=6+x^2 in the original int

damn man...all u have to do is sub x=-2 for both sides.....(x+2)Q(x) will cancel out and the other side will have numbers and blah bloody blah....yeh....a=19