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Hi, Sorry i skipped a couple of steps. In the primitive 2[-1/2 cos2x][0 to pi/2] That becomes 2[(-1/2) (cos(pi)) - ((-1/2)cos(0))] <--- The definition of a definite integral = 2 [ (-1/2)(-1) - (-1/2)(1) ] = 2 [ 1/2 - (-1/2) ] = 2 [ 1/2 + 1/2 ] = 2 :)

Hi, As said before the graph cuts the axis at pi/2 so take the absolute value of the areas and add them together. As Sin 2x is the same above and below the axis just multiply the integral from 0 - pi/2 by 2. So..... y = sin 2x x = 0 x = pi Therefore: Int(0 to pi) sin 2x dx = 2 Int(0 to...