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Thanks, I will work on it!

But doesn't the squre inside the squareroot eliminate any possible negative values derived from cos, hence shouldn't squareroot of (square of cosx) be just cosx! I know the solution above by you is correct, but just finding it difficult to understand the concept behind it. example...

Sorry, but can you explain why it is?

This might sound stupid, but can someone explain why in the above solution: the (root of cos^2 x) = Absolute value of (cos x) and not just cosx Why the absolute value?

This can't be correct, since you are ignoring the cases where only two of the three o's occur together

IF you are only doing 12 units, then why not keep the General maths since you find it easy anyway - (you will not need to spend too much time revising on the work to do well ). Should always have some spare units on the side just incase. On the other hand, If you are not listening or...

Only one 6 means (1st die is a 6, 2nd is not a 6) or (1st die not a 6, 2nd die is a 6). Which gives P(one 6) = 1/6*5/6 + 5/6*1/6 = 5/18 This would be the same if you drew a tree diagram!

Pretty sure (about this one i.e Prabability(sure)=35/36)) that: Answers are P(66) = 1/36 P(one six) = 5/18 P(neither 6) = 25/36 Which gives the financial Expectation = -0.2777777 = -$0.28

RHS=log_2 (1/x) + ... + log_2 (1/x^10) = log_2 ((1/x) * ... * (1/x^10)) (Log Rule-"the addition rule thing") Now (1/x) * ... * (1/x^10) = (1/x^55) (Index Law - when multiply we add the powers, i.e 1+2+3......+10 = 55) Hence the rest! (I think :P).

Any Cambridge textbooks! Hmmmm Cambridge Mathematics 4 Unit by D. Arnold and G. Arnold Solutions by Sami El Hosri http://www.geocities.com/arnoldsol/ Thanks to boredofstudies link source :"D. R. Buchanan" Don't know about the 2 or 3 unit solutions - sorry! :o

Look at it in the reverse sense If COS (A) = 2/3 than . A = Cos^-1 (2/3) It's exactly the same thing right! :confused: ??? I think???? Can you smell what the ROCK is cooking! Ke ke ke ke