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I have an extension test tomorrow and there are three questions I couldn't get out... I'm sure I just made a stupid mistake when doing them though because they arn't that difficult. The second one I got one correct solution but couldn't get the other for some reason... ANGLE BETWEEN TWO...

I need to find some notes comparing the two films as well as on film techniques and other effects used... Does anyone have any, or know where I can find some?

Ill have to go back over it again... Also... What are linear factors?

I was asked to write this as a product of its factors... x³ - 7x + 6 After dividing by (x-1) I got x² - x - 6 With division transformation it became (x - 1)(x² - x - 6) broken down into (x - 1)(x + 2)(x - 3) Is this correct? The text book got (x - 1)(x - 2)(x + 3) Iv...

How do I factorise this? (x+1)(3x³+8x²+7x+2) Iv tried a few ways but cant seem to get the right answer...

How do I factorise this? (x+1)(3x³+8x²+7x+2) Iv tried a few ways but cant seem to get the right answer...

f(x)=3sin4(x-6)+5

Yeah its standard.... I forgot that when factorising with 4 terms alot of the time it can be done in pairs...

x3(x2-9)-8(x2-9) = 0 (X³-8)(X²-9) = 0 (X³-2³)(X²-3²) = 0 (X - 2) (X² + 2X + 4)(X + 3) (X - 3) = 0 X = +- 3 X = 2 Thanks :D

Factorise X^5 - 9X³ - 8X² + 72. Hence Solve X^5 - 9X³ - 8X² + 72 = 0 Im stumped...

but musn't they both be positive because they are squared?

In the extension 1 text book there was this problem... Solve: X² > A² The only solution I can see from that is |X| > |A| But the text book answer is X < -A, X > A Is the text book wrong or am I missing something?