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D is correct. Angle theta is misunderstood - it is the angle between the plane of the current (the page) and the plane of the magnetic filed (many parallel planes coming in or out of page) In this case that angle is 90 degrees. Use pythag (square root of (0.5 squared + 0.5 squared) to find L...

Hi The correct answer to this q is B I think.Use Lenz's law to answer it, and we will take answer C to show that it is incorrect. If current goes through globe from X to Y then a current moves upwards from brush Y to the handle. Now think of this current as a current in a single conductor...

Hi The correct answer to this q is B.Use Lenz's law to answer it, and we will take answer C to show that it is incorrect. If current goes through globe from X to Y then a current moves upwards from brush Y to the handle. Now think of this current as a current in a single conductor pointing...

Just a thought about q15. What if minority charges carriers are considered? Will this invalidate question?

and here are the correct answers 1. A 2.D 3. B 4. A 5. C 6. D 7. A 8. C 9. C 10. B weird q 11. B 12. A 13. A 14. B 15. D

q4 is A - think about it. C and D are the same thing really.

captain - i dont think it was a poor question - at least it had good physics. There is no other way except that it was in a vertical plane to interpret situation.

youre right in a way but remember it said that the particle was charged and was suspended i.e. stationary Therefore it had no vertical motion, so weight must have been balanced by some force. In this case, only a anttractive force from "top" plate could provide this.

Touche. But...touchy touchy.

yes - it wasn't a hard q. Positive charges repel , objects have weight - thats about it.

agree absolutely helper But I think it was a mandatory experiment - in original syllabus? Check doc with tracked changes from BOS. Anyway - thanks for your input - alwaysw good to see from another perspective.

yes - haboozin - youre right on both accounts. A curve parallel to given curve should also be OK but i'd be interested to see how that would be marked in terms of the specification that they wanted a line drawn. The original reason why i posted this was to put up for discussion something i...

helper - thanks for that - Filters "have" a range of wavelengths - thats fine and I can accept that. I guess its just a case of moving the goalposts. The links you gave - thanks for those - were all of pd vrs current, not quite the same as in exam q but there you go

Hi Helper. You could be right about an erroneous data value.....but I doubt it. There could certainly be errors in reading a current value to a certain degree of accuracy, but certainly not an error in actually recording that a current actually existed if it didn't.......ie if current at 1.2 eV...

you could well be right John - in fact it it is the only way it could be answered correctly to determine work func. But the question does say..." ....in the region where the photocurrentvaries greatest with photon energy" And its that biot which worries me. To decide when to draw a line or a...

I think q25 is incorrect. Students were asked to draw the line of best fit thgrough the steepest part of the graph (i have no idea why but anyway). This gives an intercept value on x-axis of about 1.60 eV. In part b of q, studnets have to use this line to determine work function. Of course most...