Another trig question (graph) (1 Viewer)

YBK

w00t! custom status!! :D
Joined
Aug 22, 2004
Messages
1,240
Location
47 |)35|< !!!
Gender
Male
HSC
2006
Could anyone please help me out on this one:

Write cosx - sinx in the form Rcos(x+b) where R>0, 0<b<90


Well, i could do this part

(1/R^2) + (1/R^2) = 1

R= root 2 (don't know how to do root sign)

root 2 cos (x +45)

I could do that part, but the next part asked\:

Hence sketch the graph y= cosx - sinx, 0 < x < 360, marking the intercepts on the axis and marking on the axes the y and x values at the turning points.


Alright, I know that the y intercept is 1.
The maximum and minimum points are root2 and - root2
x intercepts are 45, 225

but when it comes to finding x when y = root 2 i get stuck

i get something like this after replacing y with root 2 to get the x value when y is root 2

root 2 = cosx - sinx

How do u solve that?

Thanks again! :)

Edit: added answer to first part
 
Last edited:

rama_v

Active Member
Joined
Oct 22, 2004
Messages
1,151
Location
Western Sydney
Gender
Male
HSC
2005
YBK said:
Could anyone please help me out on this one:

Write cosx - sinx in the form Rcos(x+b) where R>0, 0<b<90


Well, i could do this part

(1/R^2) + (1/R^2) = 1

R= root 2 (don't know how to do root sign)

root 2 cos (x +45)

I could do that part, but the next part asked\:

Hence sketch the graph y= cosx - sinx, 0 < x < 360, marking the intercepts on the axis and marking on the axes the y and x values at the turning points.


Alright, I know that the y intercept is 1.
The maximum and minimum points are root2 and - root2
x intercepts are 45, 225

but when it comes to finding x when y = root 2 i get stuck

i get something like this after replacing y with root 2 to get the x value when y is root 2

root 2 = cosx - sinx

How do u solve that?

Thanks again! :)

Edit: added answer to first part
the whole point of the transformation into RCos is so that you can solve your question and hence graph it :p
so anyway it becomes root 2 = root 2 cos (x +45)
1 = cos(x+45)
x + 45 = 0, 360
x = 360 - 45 = 315
 

YBK

w00t! custom status!! :D
Joined
Aug 22, 2004
Messages
1,240
Location
47 |)35|< !!!
Gender
Male
HSC
2006
rama_v said:
the whole point of the transformation into RCos is so that you can solve your question and hence graph it :p
so anyway it becomes root 2 = root 2 cos (x +45)
1 = cos(x+45)
x + 45 = 0, 360
x = 360 - 45 = 315
cool! thanks!!!

much better than what i was trying to do.... :)

can anyone solve root2 = cosx - sinx though?

is there a way to do that?
 

rama_v

Active Member
Joined
Oct 22, 2004
Messages
1,151
Location
Western Sydney
Gender
Male
HSC
2005
YBK said:
cool! thanks!!!

much better than what i was trying to do.... :)

can anyone solve root2 = cosx - sinx though?

is there a way to do that?
yes there is, it involves using the t formulae where t = tan (x/2)
Some ppl swear by the t method and will never use the transformation RCos, RSin etc. unless explicitly stated
 

currysauce

Actuary in the making
Joined
Aug 31, 2004
Messages
576
Location
Sydney
Gender
Male
HSC
2005
transformation method > t-method for all real questions hahaha
 

YBK

w00t! custom status!! :D
Joined
Aug 22, 2004
Messages
1,240
Location
47 |)35|< !!!
Gender
Male
HSC
2006
rama_v said:
yes there is, it involves using the t formulae where t = tan (x/2)
Some ppl swear by the t method and will never use the transformation RCos, RSin etc. unless explicitly stated

ohh.. yeah, i remember

i'll try that!

Do u think they could actually ask that though?
 

Users Who Are Viewing This Thread (Users: 0, Guests: 1)

Top