• Best of luck to the class of 2024 for their HSC exams. You got this!
    Let us know your thoughts on the HSC exams here
  • YOU can help the next generation of students in the community!
    Share your trial papers and notes on our Notes & Resources page
MedVision ad

Calculus Help (1 Viewer)

Mohit7

Member
Joined
Mar 25, 2006
Messages
35
Gender
Male
HSC
2007
The Question is diferentiate using the product rule.

2 3
x (x+1)
 
P

pLuvia

Guest
If that x2(x+1)3?, if so:
d/dx[x2(x+1)3]
=2x(x+1)3+3x2(x+1)2
 

ice ken

Member
Joined
Jul 4, 2006
Messages
337
Location
adel
Gender
Male
HSC
2006
Mohit7 said:
The Question is diferentiate using the product rule.

2 3
x (x+1)
wtf... i dont get the question....

is it question 23. x(x+1)

if it is its just x+1 + x = 2x+1

use u'v+uv'
u=x, v =(x+1)

expanding wouldve been quicker
 

ice ken

Member
Joined
Jul 4, 2006
Messages
337
Location
adel
Gender
Male
HSC
2006
SoulSearcher said:
Which simplifies to x(x+1)2[2(x+1)+3x]
= x(x+1)2[2x+2+3x]
= x(5x+2)(x+1)2
do u have to simplify it in sydney cause here we are not suppose in the exam. they say do not simplify the answers unless we need to use them to find like stationary points or points of inflections.
 

acmilan

I'll stab ya
Joined
May 24, 2004
Messages
3,989
Location
Jumanji
Gender
Male
HSC
N/A
The only reason they'd explicitly tell you not to simplify is probably when doing so would be difficult and/or time consuming.
 

SoulSearcher

Active Member
Joined
Oct 13, 2005
Messages
6,757
Location
Entangled in the fabric of space-time ...
Gender
Male
HSC
2007
ice ken said:
do u have to simplify it in sydney cause here we are not suppose in the exam. they say do not simplify the answers unless we need to use them to find like stationary points or points of inflections.
Normally over here you would try and simplify it to its simplest factors. And what acmilan said as well.
 

ice ken

Member
Joined
Jul 4, 2006
Messages
337
Location
adel
Gender
Male
HSC
2006
SoulSearcher said:
Normally over here you would try and simplify it to its simplest factors. And what acmilan said as well.
well yeh last yr exam q was 2find dy/dx if y=2x/(x^2+2x+2)
all i did was 2(x^2+2x+2) -2x(2x+2)/(x^2+2x+2)^2. didnt simply top still got marks.

2 more similar ones worth 3 marks and 4 marks for an integration 1. easy marks to scab.
 

Mohit7

Member
Joined
Mar 25, 2006
Messages
35
Gender
Male
HSC
2007
SoulSearcher said:
Which simplifies to x(x+1)2[2(x+1)+3x]
= x(x+1)2[2x+2+3x]
= x(5x+2)(x+1)2
How did you simplify it
 

Riviet

.
Joined
Oct 11, 2005
Messages
5,593
Gender
Undisclosed
HSC
N/A
Simplifying the derivative can often be helpful when determining stationary points as well as making it easier to find the second derivative or substituting points to test for concavity.
 

ice ken

Member
Joined
Jul 4, 2006
Messages
337
Location
adel
Gender
Male
HSC
2006
Mohit7 said:
How did you simplify it

common factor= x(x+1)<SUP>2 </SUP>then u get 2(x+1)+3x left over
then thats it....... i think. understand?
<SUP></SUP>
<SUP></SUP>
 

Users Who Are Viewing This Thread (Users: 0, Guests: 1)

Top