calculus (1 Viewer)

[philly2000]

Hi guys i need help with this question,

Given that

, prove that

.

thanks!

 

[me dumb]

y'=2x - 1
y'' = 2
y'-y''=2x-1-2
2x-3 = (2y - x)/x
multiply both sides by 1
(x/x)=1 so we can multiply the 1st side by (x/x) and the second side by 1. (its the same thing
(x(2x-3))/x=(2y-x)/x
(2x^2-3x)=(2y-x)/x
(2x^2-2x-x)/x
(2(x^2-x)-x)/x
y=x^2-x
sub it in
=2y-x/x

 

[philly2000]

got it thanks!