Can someone explain why we get a negative when we integrate this? (1 Viewer)

Run hard@thehsc

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shouldn't it be ln(x) + ln(1-x) + c
- but the ans says ln(x) - ln(1-x)..........
 

Run hard@thehsc

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Does it do with the fact that the log has an absolute sign - which when considering ln(1-x), we should be quite careful off, since it contains a negative x?
 

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