Can someone please verify this (1 Viewer)

[currysauce]

When doing the pendulum prac...

u graph Period (Squared)/ Length right

dep/independent (by excels definsition)

please!

 

[fi_babezy]

uh...... length is on the yaxis- and period squared is on the x axis

 

[Jaydels]

uh...... length is on the yaxis- and period squared is on the x axis

Length goes on the x-axis because it is the independent variable, and period squared on the y-axis, because it is dependent on the length

 

[jamesy_1988]

When doing the pendulum prac...

u graph Period (Squared)/ Length right

dep/independent (by excels definsition)

please!

The lenght is the independent variable in this experiment because you are measuring the time not the lenght. I tinhk thats right, well at least thats how i did it. therefore the lenght goes on the x-axis and the period squared goes on the y-axis.

Jamesy

 

[currysauce]

thanks people...

so after u work out gradient and u go 4 pi ^2/ [insert gradient here] = g

 

[acmilan]

thanks people...

so after u work out gradient and u go 4 pi ^2/ [insert gradient here] = g

Thats right.

 

[fi_babezy]

Thats right.

actually no, i read the prac again and it can be done that way or the other...if you do it the opposite way you have to swap the numbers around anyway...

"x- axis- t^2
y-axis length"
that's how it said to label them in the physics contexts book.