Can someone prove this for me (reward) (2 Viewers)

[Will]

Can someone prove for me the following:
show there are no non-zero integers a, b, c, n with n > 2 such that a^n + b^n = c^n

I will give $50 to anyone who can prove it for me. It's urgent, thanks if you can!

(tehehe for anyone who got the allusion)

 

[-=«MÄLÅÇhïtÊ»=-]

is this a trick?

that equation works
ie. pythagorus' theorem

 

[Dumbarse]

whats the allusion??

are a, b, c, n different numbers??, or can they be the same??

 

[-=«MÄLÅÇhïtÊ»=-]

whoops my bad
didnt catch n>2

 

[Lazarus]

Heh - he's referring to Fermat's Last Theorem. I think there was a UK$1,000,000 prize being offered for a correct proof at one stage. No-one has managed to prove it for the general case yet.

http://www-gap.dcs.st-and.ac.uk/~history/HistTopics/Fermat's_last_theorem.html

 

[-=«MÄLÅÇhïtÊ»=-]

ok
so who do I contact for the reward, i've got solution

jk

 

[Lazarus]

What's the fun in that, Bon? I can't give away all the secrets.

 

[Lazarus]

It's been proved for n = 1, n = 2, n = 3, n = 4 etc and I think all the way up to n = 167 or something, but not for all natural numbers n.

 

[DA]

Actually it was proved in 1994 by Andrew Wiles

 

[Lazarus]

Then I stand corrected. I think I was confusing it with Goldbach's conjecture.

 

[Will]

ok good stuff peoples
anyone wanna prove riemann's hypothesis? i'll give you $150 for that

 

[mannnnndy]

why r u offering so much money 4 this? u sound pretty deperate.

 

[Will]

the riemann hypothesis can be neither proved or disproved
there's a 7 million dollar prize for solving it though

 

[Will]

lol, funny that
you know sir, my interest in fermat's last theorem stemmed from visiting your website months ago

 

[KeypadSDM]

Originally posted by Will
the riemann hypothesis can be neither proved or disproved
there's a 7 million dollar prize for solving it though

Nah, it's only a 1 million prize. 7 million for 7 different prizes, making 1 million each.

 

[turtle_2468]

It was US though... which was a lot better a year ago than now, but still.
And btw I think Goldbach is now worth nothing, faber & faber offered 2 million on it for a while but then that expired last year...

also note that the poincare conjecture (one of the 7 problems) has a proof which seems correct, I think drbuchanan pointed it out before as well..

 

[KeypadSDM]

Yeah, if he submits it to a mathematics journal, and it remains accepted over a 2 year period, he makes some sweet bucks.

 

[ND]

Actually he had posted in this thread. I don't know what happened to his posts...

The allusion is to drbuchanan. I think this whole thread is a mockery of him.

Check the date, this thread was posted long, long ago.

 

[Grey Council]

o

who made this alive? And Buchanan deletes his posts, for some reason that escapes me. :|

 

[+Po1ntDeXt3r+]

Originally posted by drbuchanan

Prove that if n is a positive integer and
d(n)=sum of the positive divisors of n and
h(n)=1/1+1/2+1/3+...+1/n then
d(n)<=h(n)+e^h(n)ln(h(n)).

Stick tat as Question 9 on a 4 u exam.. dun tell the students there is no answer.. and go claim the prize "for 1 million dollars"... evil NSW Board of studies examiners ...