Chem Radioisotopes (1 Viewer)

norez

Member
Joined
Aug 16, 2009
Messages
61
Gender
Female
HSC
2011
Does anyone know the decay reaction for iodine-123? I've looked online, in my textbook and in the resources. Even if it's just a word equation :)

Any help would be appreciated.
 
K

khorne

Guest
Why do you need the decay series? It will never ask it. It might ask how it's produced, but not it's decay. But suffice to say, it will decay with a combination of gamma and beta decay
 

b3kh1t

Member
Joined
May 21, 2010
Messages
271
Gender
Male
HSC
2011
Does anyone know the decay reaction for iodine-123? I've looked online, in my textbook and in the resources. Even if it's just a word equation :)

Any help would be appreciated.
It decays into Tellerium-123 producing beta and gamma radiation.

 

lpodnano

5eva alone
Joined
Mar 6, 2008
Messages
1,561
Location
;)
Gender
Female
HSC
2011
Btw I'm going to steal this thread. How do you do the MC question 20 in 2010? I know it's pathetic to struggle at MC, but I can't do it!
 
K

khorne

Guest
Btw I'm going to steal this thread. How do you do the MC question 20 in 2010? I know it's pathetic to struggle at MC, but I can't do it!
Line for atomic absorbance is y = mx

concentration 0, abs = 0
concentration 10, abs = 0.4
so gradient is 0.4/10, abs = 0.4/10 * conc.

therefore conc at 0.5 = 12.5 ppm, etc
 

jamesfirst

Active Member
Joined
Jan 30, 2010
Messages
2,005
Gender
Male
HSC
2011
Btw I'm going to steal this thread. How do you do the MC question 20 in 2010? I know it's pathetic to struggle at MC, but I can't do it!
why is it pathetic...


Sometimes the MC is fked up
 

b3kh1t

Member
Joined
May 21, 2010
Messages
271
Gender
Male
HSC
2011
Btw I'm going to steal this thread. How do you do the MC question 20 in 2010? I know it's pathetic to struggle at MC, but I can't do it!
Lol it's quite simple to start a new thread but anyway.

As the curve will be linear or close to it, we can say
which equals 12.5 mg/L

therefore Cu2+ in 100 mL is 1/10x12.5=1.25 mg
number of moles of Cu2+= 0.00125/65.55 = 1.97x10^-5 moles



therefore number of moles of Cu2+ = number of moles of CuCO3
number of moles of CuCO3 = 1.97x10^-5
therefore mass of CuCO3 = 1.97x10^-5 x 123.55 = 2.43x10^-3g

therefore answer is (B), oh and don't worry multiply choice is hard so it's not pathetic
 
Last edited:

Users Who Are Viewing This Thread (Users: 0, Guests: 1)

Top