given:
1. DCF is right angled.
2. D and F are circle centres. (normal of tangent to a circle passes circle centre)
rtp: DEF is right angled.
let E be the 2nd intersection pt between the circles.
construct DE & FE.
1. CF = EF (equal radii)
2. CD = ED (similarly)
3. DF is common.
thus CDF is cong. to DEF (SSS)
so DEF is right angled (corresp. angles in sim. tri.)