Using Aural_Sax's Derived Formula F= mv^2/R
Sub in All the Values, Giving
F= 600Kg * (10ms^-1)^2 // 10
F= 100N
Using Common Sense, It is going horizontally Down.
Therefore, The force on the Track is 100N Down.
(Haven't proofread, Don't Crucify me if there are Typos)