Complex 2 (1 Viewer)

[=)(=]

 

[=)(=]

I get how you bring everything under ^ and have rhs=-1=cispi but not sure where to go after

 

[Trebla]

Easiest way is to just substitute each given root into the LHS and show it equals zero.

 

[yanujw]

I get how you bring everything under ^ and have rhs=-1=cispi but not sure where to go after

Continuing from that step, let the fraction be rcistheta, then...






You could then say, similarly, for z-1/z+1=cis(3pi/4), z=cot(3pi/8) etc. Then you have derived all the 4 solutions.

 

[=)(=]

tysm

 

[ExtremelyBoredUser]

Continuing from that step, let the fraction be rcistheta, then...
View attachment 36379

View attachment 36380

View attachment 36381

You could then say, similarly, for z-1/z+1=cis(3pi/4), z=cot(3pi/8) etc. Then you have derived all the 4 solutions.

damn thats pre smart using desmos for typing sols out

 

[Life'sHard]

damn thats pre smart using desmos for typing sols out

Lol just use latex